NEET AIPMT SOLVED PAPER 2000

  • question_answer
                    The factor of \[\Delta G\] values is important in metallurgy. The \[\Delta G\] values for the following reactions at 800°C are given as:                                                                                                                                                                     \[\begin{align}   & {{S}_{2}}(s)+2{{O}_{2}}(g)\to 2S{{O}_{2}}(g)\,;\,\Delta G=-544\,kJ \\  & 2Zn(s)+{{S}_{2}}O\to \,2ZnS(s)\,;\Delta G=-293kJ \\  & 2Zn(s)+{{O}_{2}}(g)\to 2ZnO(s);\Delta G=-480\,kJ \\ \end{align}\]                 Then \[\Delta G\]  for the reaction  \[2ZnS(s)+3{{O}_{2}}(g)\xrightarrow{{}}2ZnO(s)+2S{{O}_{2}}(g)\] will be:                  

    A)                 -357 kJ 

    B)                 -731 kJ 

    C)                 -773 kJ 

    D)                 -229 kJ

    Correct Answer: B

    Solution :

                    \[\Delta G\] of formation of different substances are as                 \[2\,S{{O}_{2}}\,=-544\,kJ\]                 \[2ZnS=-293\,kJ\]                 \[2ZnO=-480\,kJ\]                 For the reaction                 \[2ZnS+3{{O}_{2}}(g)\xrightarrow[{}]{{}}2ZnO(s)+2S{{O}_{2}}(g)\]                 \[\Delta G=[\Delta {{G}_{(products)}}-\Delta {{G}_{(reac\tan ts)}}]\]                 \[=[(-480)+(-544)-(-293)]\]                 \[=-1024+293\]                 = - 731 kJ


You need to login to perform this action.
You will be redirected in 3 sec spinner