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NEET AIPMT SOLVED PAPER 2000

  • question_answer
                    Assuming fully decomposed, the volume of \[C{{O}_{2}}\] released at STP on heating 9.85g of \[BaC{{O}_{3}}\] (Atomic mass, Ba = 137) will be:                                                                                                                                                

    A)                 1.12 L    

    B)                 0.84 L    

    C)                 2.24 L    

    D)                 4.06 L

    Correct Answer: A

    Solution :

                                   On decomposition \[BaC{{O}_{3}}\] liberates \[C{{O}_{2}}\] as                 \[\underset{197}{\mathop{BaC{{O}_{3}}}}\,\xrightarrow{{}}BaO+\underset{22.4\,L\,at\,STP}{\mathop{C{{O}_{2}}\uparrow }}\,\]                 \[\because \]     \[197\,g\,BaC{{O}_{3}}\] gives \[=22.4\,L\] of \[C{{O}_{2}}\] at STP                 \[\because \]     \[9.85\,g\,BaC{{O}_{3}}\] will give \[=\frac{22.4\times 9.85}{197}=1.12\,L\]


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