question_answer

                The correct structure of \[Fe{{(CO)}_{5}}\] is:                                                                                                    

A)                 trigonal bipyramidal       

B)                 octahedral         

C)                 tetrahedral                                                        

D)                 square pyramidal

Correct Answer: A

Solution :

                                                 In, \[Fe{{(CO)}_{5}},\] the Fe atom is in \[ds{{p}^{3}}\] hybridised state. Therefore, the shape of molecule is trigonal bipyramidal. The hybridisation is as                 \[_{26}Fe=1{{s}^{2}},\,\,2{{s}^{2}}\,2{{p}^{6}},\,3{{s}^{2}}\,3{{p}^{6}}\,3{{p}^{6}},\,4{{s}^{2}}\,4{{p}^{0}}\]                 In \[Fe{{(CO)}_{5}}\] the 'Fe' atom is -