A) sodium ethoxide
B) ethyl chloride
C) dry \[HCl-{{C}_{2}}{{H}_{5}}OH\]
D) ethanol
Correct Answer: C
Solution :
Ethyl benzoate is prepared by reacting benzoic acid and ethanol in presence of dry HCl. This reaction is known as esterification reaction. \[\begin{align} & \underset{Benzoic\,acid}{\mathop{{{C}_{6}}{{H}_{5}}COOH}}\,+\underset{Ethanol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\underset{Dry}{\mathop{\xrightarrow{HCl}}}\, \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underset{Ethyl\,\,benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}+{{H}_{2}}O}}\, \\ \end{align}\]
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