A) \[\frac{1}{4}\]
B) \[\frac{1}{8}\]
C) \[\frac{1}{16}\]
D) \[\frac{1}{32}\]
Correct Answer: C
Solution :
Probability of having a son in one delivery =1/2 \[\therefore \] probability of having four sons in four deliveries \[=\frac{1}{2}\,\times \frac{1}{2}\,\times \frac{1}{2}\,\times \frac{1}{2}\,=\frac{1}{16}\]
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