NEET AIPMT SOLVED PAPER 2001

  • question_answer
                    The wavelength corresponding to maximum intensity of radiation emitted by a source at temperature 2000K is \[\lambda \], then what is the wavelength corresponding to maximum intensity of radiation at temperature 3000 K?

    A)                                                                                                                                                                                                            \[\frac{2}{3}\lambda \] 

    B)                 \[\frac{16}{81}\lambda \]            

    C)                 \[\frac{81}{16}\lambda \]            

    D)                 \[\frac{4}{3}\lambda \]

    Correct Answer: A

    Solution :

                              Key Idea: The relation between the wavelength corresponding to maximum intensity of radiation at any temperature is given by Wien?s displacement law.                 Wien?s displacement law is given by                 \[{{\lambda }_{m}}T=\text{cosntant}\]                         \[or{{\lambda }_{1}}{{T}_{1}}={{\lambda }_{2}}{{T}_{2}}\]                         \[or{{\lambda }_{2}}={{\lambda }_{1}}\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)\]                 Here, \[{{T}_{1}}=2000\,K,\,{{T}_{2}}=3000\,K,\,{{\lambda }_{1}}=\lambda \]                         \[\therefore {{\lambda }_{2}}=\lambda \times \frac{2000}{3000}=\frac{2}{3}\,\lambda \]


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