A) q = w = 500 J, \[\Delta \]U = 0
B) q = \[\Delta \]U = 500 J, w = 0
C) q = w = 500 J, \[\Delta \]U = 0
D) \[\Delta \]U = 0, q = w = -500 J
Correct Answer: B
Solution :
As we know that \[\Delta H=\Delta E+P\Delta V\] When \[\Delta V=0\] \[\therefore \] \[\Delta H=\Delta E\] From first law of thermodynamics \[\Delta E=q-W\] In given problem \[\Delta H=500\,J\] \[-W=-p\Delta V,\] \[\Delta V=0\] So, \[\Delta E=q=500\,J\]You need to login to perform this action.
You will be redirected in
3 sec