A) \[F{{e}^{3+}}\] increases
B) \[F{{e}^{3+}}\] decreases
C) \[\frac{F{{e}^{2+}}}{F{{e}^{3+}}}\] remains unchanged
D) \[F{{e}^{2+}}\] decreases
Correct Answer: B
Solution :
The metals have higher negative values of their electrode potential can displace metals having lower values from their salt solution. So \[F{{e}^{3+}}\] decreases.You need to login to perform this action.
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