A) x > y
B) x < y
C) x = y
D) x > y
Correct Answer: A
Solution :
\[C{{H}_{4}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{H}_{3}}OH(l)\] \[\therefore \Delta H=-[(\Delta H\,of\,combustion\,of\,C{{H}_{3}}OH)\] -(\[\Delta H\] of combustion of CH4)] \[\begin{align} & =-[(-y)-(-x)] \\ & =-[-y+x]=y-x \\ \end{align}\] \[\therefore \,\,x>y\]You need to login to perform this action.
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