NEET AIPMT SOLVED PAPER 2001

  • question_answer
                    Current is flowing in a coil of area A and number of turns N, then magnetic moment of the coil M is equal to:

    A)                                                                                                                                                                                                            \[NiA\]

    B)                 \[\frac{Ni}{A}\]                

    C)                 \[\frac{Ni}{\sqrt{A}}\]   

    D)                            \[{{N}^{2}}Ai\]

    Correct Answer: A

    Solution :

                              If there are N turns in a coil, i is the current flowing and A is the area of the coil then magnetic dipole moment or simply magnetic moment of the coil is                 M = NiA


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