NEET AIPMT SOLVED PAPER 2001

  • question_answer
                    In X-rays diffraction experiment distance between atomic lattice planes of diffraction grating is \[2.8\times {{10}^{-10}}\,m\], then the maximum wavelength of X-rays (in metre) is:                                                                            

    A)                 2.5                         

    B)                 \[5.6\times {{10}^{-10}}\]

    C)                 \[4\times {{10}^{-10}}\]

    D)                 \[4.6\times {{10}^{-10}}\]

    Correct Answer: B

    Solution :

                    Key Idea: From Bragg?s law, the condition for the reflection of X-rays from series of atomic layers in a given plane is,                 \[2d\,\sin \theta =n\lambda \]                 From key idea,                 wavelength \[\lambda =\frac{2d\,\sin \theta }{n}\]                 \[{{\lambda }_{\max }}=\frac{2\,d\,{{(\sin \,\theta )}_{\max }}}{n}\]                 \[=\frac{2\,d\times 1}{1}\,[\because \,\,{{(\sin \theta )}_{\max }}=1]\]                 = 2d                 \[=2\times 2.8\times {{10}^{-10}}\,m\]                 \[=5.6\times {{10}^{-10}}\,m\]                 Note:    Bragg?s reflection can occur only for wavelength \[\lambda \le 2d\]. Due to this fact, the visible light wavelength cannot be used in diffraction.


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