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NEET AIPMT SOLVED PAPER 2001

  • question_answer
                      In a common-base configuration of a transistor \[\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}=0.98\] then current gain in common emitter configuration of transistor will be:                                                                                                          

    A)                 49                          

    B)                 98          

    C)                            4.9                         

    D)                 24.5

    Correct Answer: A

    Solution :

                    Key Idea: \[\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}\,\]is the current gain \[(\alpha )\] in common-base configuration.                 \[\alpha =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}\,=\,0.98\]                 The current gain in common-emitter configuration                 \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.98}{1-0.98}\]                 \[=\frac{0.98}{0.02}=49\]


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