A) \[\frac{3}{50}\,A\]
B) \[\frac{5}{50}\,A\]
C) \[\frac{4}{50}A\]
D) \[\frac{2}{50}\,A\]
Correct Answer: B
Solution :
In the circuit, diode \[{{D}_{1}}\] is forward biased and diode \[{{D}_{2}}\] is reverse biased. Therefore, no current flows in the arm containing \[{{D}_{2}}\] and all of the current flows through arm containing \[{{D}_{1}}\]. Thus, current flowing through the circuit \[=\frac{5}{20+30}=\frac{5}{50}\,A\]
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