A) 3
B) 6
C) 4
D) 2
Correct Answer: B
Solution :
Co-ordination number of nickel in \[{{[Ni{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{4-}}\]is 6 because \[{{C}_{2}}O_{4}^{2-}\] is bidentate ion and number of \[{{C}_{2}}O_{4}^{2-}\,\] is 3.You need to login to perform this action.
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