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NEET AIPMT SOLVED PAPER 2001

  • question_answer
                    Standard electrode potentials are:                                                                                                                           \[F{{e}^{2+}}/Fe\],                          \[{{E}^{o}}=-0.44\]                 \[F{{e}^{3+}}/F{{e}^{2+}}\],                        \[{{E}^{o}}=0.77\]                 \[F{{e}^{2+}},\,F{{e}^{3+}}\] and Fe block are kept together, then:                         

    A)                 \[F{{e}^{3+}}\] increases                                             

    B)                 \[F{{e}^{3+}}\] decreases

    C)                 \[\frac{F{{e}^{2+}}}{F{{e}^{3+}}}\] remains unchanged                 

    D)                 \[F{{e}^{2+}}\] decreases

    Correct Answer: B

    Solution :

                    The metals have higher negative values of their electrode potential can displace metals having lower values from their salt solution. So \[F{{e}^{3+}}\] decreases.


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