NEET AIPMT SOLVED PAPER 2001

  • question_answer
                                      Coordination number of \[Ni\] in \[{{[Ni{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{4-}}\] is:                                                                

    A)                 3                             

    B)                 6                             

    C)                 4                             

    D)                 2

    Correct Answer: B

    Solution :

                    Co-ordination number of nickel in \[{{[Ni{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{4-}}\]is 6 because \[{{C}_{2}}O_{4}^{2-}\] is bidentate ion and number of \[{{C}_{2}}O_{4}^{2-}\,\] is 3.


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