question_answer

                Which statements is incorrect?                                                                                                                 

A)                 \[Ni{{(CO)}_{4}}\]-Tetrahedral, paramagnetic    

B)                 \[Ni(CN)_{4}^{2-}\]-Square planar, diamagnetic

C)                 \[Ni{{(CO)}_{4}}\]-Tetrahedral, diamagnetic

D)                 \[{{[Ni{{(Cl)}_{4}}]}^{2-}}\] Tetrahedral, paramagnetic

Correct Answer: A

Solution :

                In \[Ni{{(CO)}_{4}},\,Ni\] has zero oxidation number                 So \[_{28}Ni\,=1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{6}},\,3{{s}^{2}}3{{p}^{6}}3{{d}^{8}},\,4{{s}^{2}}\]                 In excited state and during the formation of \[Ni{{(CO)}_{4}}\] \[\to \]                                   Hence in it, no unpaired electron is present. So it shows the property of diamagnetism and tetrahedral structure.