A) \[{{I}^{-}}>N{{H}_{3}}>RN{{H}_{2}}>H{{S}^{-}}\]
B) \[N{{H}_{3}}>RN{{H}_{2}}>H{{S}^{-}}>{{I}^{-}}\]
C) \[RN{{H}_{2}}>N{{H}_{3}}>H{{S}^{-}}>{{I}^{-}}\]
D) \[H{{S}^{-}}>RN{{H}_{2}}>N{{H}_{3}}>{{I}^{-}}\]
Correct Answer: C
Solution :
Basic strength \[\propto \] rate of accepting of proton. In \[R-\overset{\centerdot \,\,\centerdot }{\mathop{N}}\,{{H}_{2}},\,N-\]has lone pair of electron which intensify due to electrons releasing R?group and increase the tendency to donate lone pair of electrons to \[{{H}^{+}}\]. Secondly as the size of the ion increases, there is less attraction for \[{{H}^{+}}\] as form weaker bond with H?atom and less basic. The order of the given series: \[RN{{H}_{2}}>N{{H}_{3}}>H{{S}^{-}}>{{I}^{-}}\]
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