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NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    A diseased man marries a normal woman and they get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is:                                                      

    A)                 sex-linked dominant

    B)                 sex-linked recessive

    C)                 sex-limited character                                    

    D)                 autosomal dominant

    Correct Answer: A

    Solution :

                                                              Since the father is diseased and daughters also?die disease is not sex-limited of course, it is sex-linked. Sex linked inheritance may be X-linked as given in the question, Y-linked and XY-linked.                 In X-linked inheritance the characters are controlled by genes located on non homologous part of X-chromosome. These X-linked genes do not have their corresponding alleles on Y-chromosome. In daughter it is express even when present in heterozygous condition.


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