A) 0.80 M
B) 1.0 M
C) 0.73 M
D) 0.50 M
Correct Answer: C
Solution :
Moles of 2.5 L of 1 M NaOH \[=2.5\times 1=2.5\] Moles of 3.0 L of 0.5 M NaOH \[=3.0\times 0.5\,=1.5\] Total moles of NaOH in solution \[=2.5+1.5=4.0\] (Total volume of solution = 2.5 + 3.0 = 5.5 L) Thus \[{{M}_{1}}\times {{V}_{1}}={{M}_{2}}\times {{V}_{2}}\] \[4.0={{M}_{2}}\times 5.5\] \[\therefore \,\,Molarity\,of\,resul\tan t\,\,solution={{M}_{2}}=\frac{4.0}{5.5}M\] \[\approx \,\,0.73\,\,M\]You need to login to perform this action.
You will be redirected in
3 sec