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NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    The following particles are moving with the same velocity, then maximum de-Broglie wavelength will be for:

    A)                                                                                                                                                                                            proton   

    B)                 \[\alpha \]-particle         

    C)                 neutron            

    D)                 \[\beta \]-particle

    Correct Answer: D

    Solution :

                    de-Broglie wavelength is given by                 \[\lambda =\frac{h}{mv}\]                 For same velocity,                 \[\lambda \,\propto \frac{1}{m}\]                 Out of the given particles, the mass of \[\beta \]-particle which is a fast moving electron, is minimum. Thus, de-Broglie wavelength is maximum for \[\beta \]-particle.


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