A) 6
B) 12
C) 24
D) 48
Correct Answer: C
Solution :
Given \[\frac{{{I}_{C}}}{{{I}_{E}}}=Current\,gain\,(\alpha )=0.96\] So, current gain in common emitter configuration is \[\beta =\frac{\alpha }{1-\alpha }\] \[=\frac{0.96}{1-0.96}-\frac{0.96}{0.04}\] = 24 Note: The current gain \[\beta \] in common emitter mode is very large as compared to the current gain \[\alpha \] in common base mode. This is why a transistor is always used as an amplifier in the CE mode.
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