NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    A capacitor of capacity \[{{C}_{1}}\] is charged upto potential V volt and then connected in parallel to an uncharged capacitor of capacity \[{{C}_{2}}\]. The final potential difference across each capacitor will be:

    A)                            \[\frac{{{C}_{2}}V}{{{C}_{1}}+{{C}_{2}}}\]             

    B)                 \[\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]             

    C)                 \[\left( 1+\frac{{{C}_{2}}}{{{C}_{1}}} \right)V\]  

    D)                 \[\left( 1-\frac{{{C}_{2}}}{{{C}_{1}}} \right)V\]

    Correct Answer: B

    Solution :

                    The common potential difference across two capacitors connected in parallel                 \[V'=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\]                 \[Here,{{V}_{1}}=V,\,\,\,{{V}_{2}}=0\]                 \[\therefore V'=\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]


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