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NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    For a cell the terminal potential difference is 2.2 V when circuit is open and reduces to 1.8 V when cell is connected to a resistance R = 5 \[\Omega \], the internal resistance (r) of cell is:                                              

    A)                 \[\frac{10}{9}\Omega \]               

    B)                 \[\frac{9}{10}\,\Omega \]           

    C)                 \[\frac{11}{9}\Omega \]               

    D)                 \[\frac{5}{9}\Omega \]

    Correct Answer: A

    Solution :

                    In an open circuit, emf of cell                 E = 2.2 V                 In a closed circuit, terminal potential difference                 V = 1.8 V                 External resistance, R = 5 \[\Omega \]                 Thus, internal resistance of cell is                 \[r=\left( \frac{E}{V}-1 \right)\,\,R=\left( \frac{2.2}{1.8}-1 \right)\,5\]                 \[=\left( \frac{11}{9}-1 \right)\,5=\frac{2}{9}\times 5=\frac{10}{9}\Omega \]


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