A) \[5\times {{10}^{-12}}\]
B) \[25\times {{10}^{-10}}\]
C) \[1\times {{10}^{-13}}\]
D) \[5\times {{10}^{-13}}\]
Correct Answer: D
Solution :
\[\underset{\begin{smallmatrix} \text{Solubility}\,0.5\times {{10}^{-4}} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,M \end{smallmatrix}}{\mathop{M{{X}_{2}}}}\,\xrightarrow{\,}\,\underset{\begin{smallmatrix} 0.5\times {{10}^{-4}} \\ \,\,\,\,\,\,M \end{smallmatrix}}{\mathop{{{M}^{2+}}}}\,+\underset{\begin{smallmatrix} 2\times 0.5\times {{10}^{-4}} \\ \,\,\,\,\,\,\,\,M \end{smallmatrix}}{\mathop{2{{X}^{-}}}}\,\] (on 100% ionization) \[\therefore \,\,{{K}_{s}}p\] of \[M{{X}_{2}}=[{{M}^{2+}}]\,{{[{{X}^{-}}]}^{2}}\] \[=(0.5\times {{10}^{-4}})\,{{(1.0\times {{10}^{-4}})}^{2}}\] \[=0.5\times {{10}^{-12}}=5\,\times {{10}^{-13}}\]
You need to login to perform this action.
You will be redirected in
3 sec
