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NEET AIPMT SOLVED PAPER 2002

  • question_answer
    .                 1 M and 2.5 litre NaOH solution mixed with another 0.5 M and 3 L NaOH solution. Then find out molarity of resultant solution.                                                                                                                                          

    A)                 0.80 M    

    B)                 1.0 M    

    C)                 0.73 M   

    D)                 0.50 M

    Correct Answer: C

    Solution :

                    Moles of 2.5 L of 1 M NaOH \[=2.5\times 1=2.5\]                 Moles of 3.0 L of 0.5 M NaOH \[=3.0\times 0.5\,=1.5\]                 Total moles of NaOH in solution \[=2.5+1.5=4.0\]                 (Total volume of solution = 2.5 + 3.0 = 5.5 L)                 Thus      \[{{M}_{1}}\times {{V}_{1}}={{M}_{2}}\times {{V}_{2}}\]                 \[4.0={{M}_{2}}\times 5.5\]                 \[\therefore \,\,Molarity\,of\,resul\tan t\,\,solution={{M}_{2}}=\frac{4.0}{5.5}M\]                 \[\approx \,\,0.73\,\,M\]


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