A) \[C{{H}_{3}}COOK\]
B) \[N{{a}_{2}}C{{O}_{3}}\]
C) \[N{{H}_{4}}Cl\]
D) \[NaN{{O}_{3}}\]
Correct Answer: A
Solution :
\[pH=\log \,\frac{1}{[{{H}^{+}}]}\] pH is inversely proportional to hydrogen ion concentration. As concentration of \[{{H}^{+}}\]decreases pH increases and vice versa. Ammonium chloride \[(N{{H}_{4}}Cl)\] is a salt of weak base and strong acid. So, its aqueous solution will be acidic as \[N{{H}_{4}}Cl+{{H}_{2}}O\to \,\underset{Weak\,base}{\mathop{N{{H}_{4}}OH}}\,+\underset{Strong\,acid}{\mathop{HCl}}\,\] So, pH of \[N{{H}_{4}}Cl\] is less than 7. \[NaN{{O}_{3}}\] (Sodium nitrate) is the salt of strong acid and strong base. So, its aqueous solution is neutral as \[NaN{{O}_{3}}+{{H}_{2}}O\to \,\underset{Strong\,base}{\mathop{NaOH}}\,+\underset{Strong\,acid}{\mathop{HN{{O}_{3}}}}\,\] So, pH of \[NaN{{O}_{3}}\] is 7. \[C{{H}_{3}}COOK\] (Potassium acetate) is a salt of strong base and weak acid, its aqueous solution will be basic and pH value will be \[>\,7\approx \,8.8\] \[C{{H}_{3}}COOK+{{H}_{2}}O\to \,\underset{Weak\,acid}{\mathop{C{{H}_{3}}COOH}}\,+\underset{Strong\,\,base}{\mathop{KOH}}\,\] Na2CO3 (Sodium carbonate) is a salt of strong base and weak acid. Its aqueous solution is also basic and its pH value will be more than 10. \[N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O\to \underset{Strong\,base}{\mathop{2NaOH}}\,+\underset{Weak\,acid}{\mathop{{{H}_{2}}C{{O}_{3}}}}\,\]
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