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NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    Solution of 0.1 N \[N{{H}_{4}}OH\] and 0.1 N \[N{{H}_{4}}Cl\] has pH 9.25, then find out \[p{{K}_{b}}\] of \[N{{H}_{4}}OH\].           

    A)                 9.25                       

    B)                 4.75                       

    C)                 3.75                       

    D)                 8.25

    Correct Answer: B

    Solution :

                    Solution of \[N{{H}_{4}}OH\] and \[N{{H}_{4}}Cl\] acts as a basic buffer solution. For basic buffer solution                 \[pOH=p{{K}_{b}}+\log \frac{[Salt]}{[Base]}\]                 \[pOH=14-pH=14-9.25=4.75\]                 \[4.75=p{{K}_{b}}+\log \frac{0.1}{0.1}\]                 \[p{{K}_{b}}=4.75\]


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