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NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    3A\[\xrightarrow{{}}\]2B, rate of reaction \[+\frac{d[B]}{dt}\]is equal to:

    A)                                                                                                           \[-\frac{3}{2}\frac{d[A]}{dt}\]   

    B)                 \[-\frac{2}{3}\frac{d[A]}{dt}\]   

    C)                 \[-\frac{1}{3}\frac{d[A]}{dt}\]   

    D)                 \[+2\frac{d\,[A]}{dt}\]

    Correct Answer: C

    Solution :

                    For reaction,                 \[3A\xrightarrow[{}]{{}}2B\]                 \[Rate\,=\,-\frac{1}{3}\,\frac{d[A]}{dt}=+\frac{1}{2}\frac{d\,[B]}{dt}\]                 \[\therefore +\frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt}\]


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