A) \[2KI+B{{r}_{2}}\to 3KBr+{{I}_{2}}\]
B) \[2KBr+{{I}_{2\,}}\to \,2KI+B{{r}_{2}}\]
C) \[2KBr+C{{l}_{2}}\to 2KCl+B{{r}_{2}}\]
D) \[2{{H}_{2}}O+2{{F}_{2}}\to 4HF+{{O}_{2}}\]
Correct Answer: B
Solution :
\[2KBr+{{I}_{2}}\xrightarrow{{}}2KI+B{{r}_{2}}\] reaction is not possible because \[B{{r}^{-}}\] ion is not oxidised in \[B{{r}_{2}}\] with \[{{I}_{2}}\] due to higher electrode potential of \[{{I}_{2}}\] than bromine. In halogens fluorine can displace chlorine bromine and iodine, chlorine can displays bromine and iodine and bromide can display iodine from their salts.
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