NEET AIPMT SOLVED PAPER 2002

  • question_answer
                    In electrolysis of NaCl when Pt electrode is taken then \[{{H}_{2}}\] is liberated at cathode while with Hg cathode it forms sodium amalgam:                                                                                                                         

    A)                 Hg is more inert than Pt

    B)                 more voltage is required to reduce \[{{H}^{+}}\] at Hg than at Pt

    C)                 Na is dissolved in Hg while it does not dissolved in Pt

    D)                 concentration of \[{{H}^{+}}\] ions is larger when Pt electrode is taken

    Correct Answer: B

    Solution :

            Sodium chloride in water dissociates as         \[NaCl\rightleftharpoons N{{a}^{+}}+C{{l}^{-}}\]         \[{{H}_{2}}O\rightleftharpoons {{H}^{+}}+O{{H}^{-}}\]                 when electric current is passed through this solution using platinum electrode, \[N{{a}^{+}}\] and \[{{H}^{+}}\] move towards cathode. Whereas \[C{{l}^{-}}\] and \[O{{H}^{-}}\] ions move towards anode.                 At cathode:                 \[{{H}^{+}}+{{e}^{-}}\xrightarrow[{}]{{}}H\]                 \[H+H\xrightarrow[{}]{{}}{{H}_{2}}\]                 At anode:-                 \[C{{l}^{-}}-{{e}^{-}}\xrightarrow[{}]{{}}\,Cl\]                 \[Cl+Cl\xrightarrow[{}]{{}}C{{l}_{2}}\]                 If mercury is used as cathode, \[{{H}^{+}}\] tons are not discharged at mercury cathode because mercury has a high hydrogen over voltage. \[N{{a}^{+}}\] ions are discharged at cathode in preference of H+ ions yielding sodium, which dissolves in mercury to form sodium amalgam.


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