A) \[N{{H}_{3}}<P{{H}_{3}}<As{{H}_{3}}\] ? acidic
B) Li < Be < B < C - 1st IP
C) \[A{{l}_{2}}{{O}_{3}}<MgO<N{{a}_{2}}O<{{K}_{2}}O\] ? basic
D) \[L{{i}^{+}}\,<N{{a}^{+}}<{{K}^{+}}<C{{s}^{+}}\]- ionic radius
Correct Answer: B
Solution :
Li, Be, B and C are present in IInd period. In a period from left to right ionisarion potential increases. \[\underset{Li\,\,\,Be\,\,B\,\,C}{\mathop{\xrightarrow{IP\,increases}}}\,\] * But in case of Be and B, Be has higher IP than B due to stable configuration of Be \[_{4}Be=1{{s}^{2}},\,2{{s}^{2}}\] \[\underset{2{{s}^{2}}}{\mathop{}}\,\,\,\text{stable configuration}\] \[_{5}B=1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{1}}\] \[\underset{2{{p}^{1}}}{\mathop{}}\,\text{ unstable configuration}\] So, the correct order of IP of given elements is Li < B < Be < C
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