A) \[C{{O}_{2}},\,N{{O}_{2}}\]
B) \[NO_{2}^{-},\,C{{O}_{2}}\]
C) \[C{{N}^{-}},\,CO\]
D) \[S{{O}_{2}},\,C{{O}_{2}}\]
Correct Answer: C
Solution :
\[C{{N}^{-}}\] and CO are iso-electronic because they have equal number of electrons. In \[C{{N}^{-}}\] the no. of electrons = 6 + 7 + 1 = 14 In CO the no. of electrons = 6 + 8 = 14
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