A) \[15\,\,m/{{s}^{2}}\]
B) \[10\,\,m/{{s}^{2}}\]
C) \[5\,\,m/{{s}^{2}}\]
D) \[0.5\,\,m/{{s}^{2}}\]
Correct Answer: C
Solution :
Key Idea: Apply Newton's second law along x-axis. Free body diagram of block is: From Newton's second law along x-axis \[\Sigma {{F}_{x}}=ma\] \[i.e.,F-f=ma\] \[orF-\mu mg=ma\] \[ora=\frac{F-\mu mg}{m}\] Given, F = 100 N, \[\mu \] = 0.5, m = 10 kg, \[g=10\,m/{{s}^{2}}\] Substituting die values in the above relation for acceleration of block, \[a=\frac{(100)-(0.5)\,(10)\,(10)}{(10)}=5\,m/{{s}^{2}}\]You need to login to perform this action.
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