A) 4.8 K
B) 6.6 K
C) 1.2 K
D) 2.4 K
Correct Answer: D
Solution :
\[C=\frac{q}{m({{T}_{2}}-{{T}_{1}})}\] (Given, that \[C=75\,\,J{{K}^{-1}}\,mo{{l}^{-1}}\], q = 1.0 kJ = 1000 J) \[75=\frac{1000}{5.55\,(\Delta T)}\,\,\left( m=\frac{100}{18}=5.55 \right)\] \[\therefore \Delta T=\frac{1000}{5.55\times 75}=2.4\,K\]You need to login to perform this action.
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