A) 6.42 V
B) 8.56 V
C) 2.14 V
D) 4.28 V
Correct Answer: C
Solution :
\[\frac{4}{3}Al+{{O}_{2}}\to \frac{2}{3}A{{l}_{2}}{{O}_{3}},\Delta G=-827\,k\,J\,mo{{l}^{-1}}\] As we know that \[\because \,\Delta G=-nEf(value\,of\,n=4)\] \[-827\times {{10}^{3}}\,J=-4\times E\times 96500\] \[E=\frac{827\times {{10}^{3}}}{4\times 96500}\]You need to login to perform this action.
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