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NEET AIPMT SOLVED PAPER 2003

  • question_answer
                    An ideal gas heat engine operates in a Carnot cycle between \[{{227}^{o}}C\] and \[{{127}^{o}}C\]. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to: 

    A)                 1.6                         

    B)                 1.2         

    C)                 4.8                         

    D)                 3.5

    Correct Answer: B

    Solution :

                           The efficiency of heat engine is \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\]                 \[or\frac{W}{{{Q}_{1}}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\]                 Here, \[{{Q}_{1}}=\] heat absorbed from the source of heat                 = 6 kcal                 \[{{T}_{1}}=\] temperature of source                 = 227 + 273 = 500 K                 and \[{{T}_{2}}=\] temperature of sink                 = 127 + 273 = 400 K                 Hence, \[\frac{W}{6}=1-\frac{400}{500}\] or            \[\frac{W}{6}=\frac{100}{500}\] or            W = 1.2 kcal                 Thus, amount of heat converted into work is 1.2 kcal.


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