NEET AIPMT SOLVED PAPER 2003

  • question_answer
                    The densities of graphite and diamond at 298 K are 2.25 and \[3.31\,\,g\,\,c{{m}^{-3}},\] respectively. If the standard free energy difference (\[\Delta \]\[{{G}^{\text{o}}}\]) is equal to 1895 J mol-1, the pressure at which graphite will be transformed into diamond at 298 K is:                                                                                                                                   

    A)                 \[9.92\times {{10}^{6}}\,Pa\]            

    B)                 \[9.92\times {{10}^{5}}\,Pa\]            

    C)                 \[9.92\times {{10}^{8}}\,Pa\]            

    D)                 \[9.92\times {{10}^{7}}Pa\]

    Correct Answer: C

    Solution :

                    The pressure at which graphite will be transformed into diamond at 298K is \[9.92\times {{10}^{8}}\,Pa\]


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