question_answer

                The compound \[\begin{align}   & \,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}} \\  & C{{H}_{3}}-\overset{|}{\mathop{C}}\,=CH-C{{H}_{3}} \\ \end{align}\] on reaction with \[NaC{{O}_{4}}\] hi the presence of \[KMn{{O}_{4}}\] gives:

A)                                                                                                                                                                                                                 \[C{{H}_{3}}COC{{H}_{3}}+C{{H}_{3}}CHO\]

B)                 \[C{{H}_{3}}CHO+C{{O}_{2}}\]

C)                 \[C{{H}_{3}}COC{{H}_{3}}\]

D)                         \[C{{H}_{3}}COC{{H}_{3}}+C{{H}_{3}}COOH\]

Correct Answer: D

Solution :