A) OR gate
B) AND gate
C) XOR gate
D) NAND gate
Correct Answer: B
Solution :
For our convenience, the output of first NAND gate is chosen as X as shown Output of first NAND gate, \[X=\overline{A\,.\,B}\] So, \[X=\bar{A}+\bar{B}\] Now, output of 2nd NAND gate, \[Y=\bar{X}\,=\overline{\bar{A}+\bar{B}}\] Again, \[\overline{\bar{A}+\bar{B}}=\bar{\bar{A}}+\bar{\bar{B}}=A.\,B\,(\because \,\,\bar{\bar{A}}=\bar{A})\] Hence, Y = A.B This is the logic function of AND gate.You need to login to perform this action.
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