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NEET AIPMT SOLVED PAPER 2003

  • question_answer
                    The solubility product of Agl at \[{{25}^{\text{o}}}C\] is \[1.0\times {{10}^{-16}}\,mo{{l}^{2}}\,{{L}^{-2}}\]. The solubility of \[AgI\] in \[{{10}^{-4}}N\] solution of KI at \[{{25}^{\text{o}}}C\] is approximately (in mol \[{{L}^{-1}}\]):                                                                                                                           

    A)                 \[1.0\times {{10}^{-10}}\]  

    B)                 \[1.0\times {{10}^{-8}}\]    

    C)                 \[1.0\times {{10}^{-16}}\]  

    D)                 \[1.0\times {{10}^{-12}}\]

    Correct Answer: D

    Solution :

                    \[AgI\xrightarrow[{}]{{}}A{{g}^{+}}+{{I}^{-}}\]                 For binary electrolyte                 \[{{K}_{sp}}={{s}^{2}}\]                 where s = solubility in mol/L                 \[1.0\times {{10}^{-16}}={{s}^{2}}\]                 or            \[s=1\times {{10}^{-8}}\,mol/L\]                 solubility of AgI in KI solution                 \[=1\times {{10}^{-8}}\,\times {{10}^{-4}}\]                 \[=1\times {{10}^{-12\,}}mol/L\]


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