A) \[{{e}_{2}}-{{e}_{1}}\]
B) \[{{e}_{1}}+2{{e}_{2}}\]
C) \[{{e}_{1}}+{{e}_{2}}\]
D) \[{{e}_{1}}-2{{e}_{2}}\]
Correct Answer: B
Solution :
\[h=\frac{1}{2}g{{t}^{2}}\] or \[g=\frac{h}{{{t}^{2}}}\] \[\therefore \] \[\log \,g=\log \,h-2\,\log \,t\] \[{{\left( \frac{\Delta g}{g}\times 100 \right)}_{\max }}=\left( \frac{\Delta h}{h}\times 100 \right)+2\left( \frac{\Delta t}{t}\times 100 \right)\] \[={{e}_{1}}+2{{e}_{2}}\]
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