A) pent-4-yn-2-ene
B) pent-3-en-1-yne
C) pent-2-en-4-yne
D) pent-1-yn-3-ene
Correct Answer: B
Solution :
\[\underset{\text{pent-3-en-1-yne}}{\mathop{\overset{5}{\mathop{C{{H}_{3}}}}\,-\overset{4}{\mathop{CH}}\,=\overset{3}{\mathop{CH}}\,-\overset{5}{\mathop{C}}\,\equiv \overset{1}{\mathop{CH}}\,}}\,\]
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