A) \[{{450}^{o}}C\]
B) \[400{}^\circ C\]
C) \[225{}^\circ C\]
D) \[30{}^\circ C\]
Correct Answer: C
Solution :
Given, \[E=30\theta -\frac{{{\theta }^{2}}}{15}\] At neutral temperature \[\frac{dE}{d\theta }=0\] \[\therefore \] \[30-\frac{2\theta }{15}=0\] \[\theta ={{225}^{o}}C\]You need to login to perform this action.
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