A) 10 mA
B) 15 mA
C) 20 mA
D) 5 mA
Correct Answer: D
Solution :
For\[\text{I}\,\text{1}\,\text{k}\,\Omega \] \[{{i}_{1}}=\frac{15}{1}=15\,\text{mA}\] For \[\text{II}\,\text{250}\,\text{ }\!\!\Omega\!\!\text{ }\] \[_{i\,\text{250}\,\text{ }\!\!\Omega\!\!\text{ }}\text{=}\frac{20-15}{250}=\frac{5}{250}\] \[\text{=}\frac{20}{1000}=20\,\text{mA}\] \[\therefore \]\[{{i}_{zener}}=20-15=5\,\text{mA}\]You need to login to perform this action.
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