A) \[{{7}^{o}}\]
B) \[{{10}^{o}}\]
C) \[{{12}^{o}}\]
D) \[5{}^\circ \]
Correct Answer: B
Solution :
For without deviation \[\frac{A}{A'}=\frac{\mu '-1}{\mu -1}\] \[\frac{{{15}^{o}}}{A'}=\frac{1.75-1}{1.5-1}\] \[\frac{15}{A'}=\frac{0.75}{0.50}\] \[A'=\frac{0.50\times 15}{0.75}={{10}^{o}}\]You need to login to perform this action.
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