A) \[\frac{1}{4}v\mathbf{\hat{i}}+\frac{3}{2}v\mathbf{\hat{j}}\]
B) \[\frac{1}{3}v\mathbf{\hat{i}}+\frac{2}{3}v\mathbf{\hat{j}}\]
C) \[\frac{2}{3}v\mathbf{\hat{i}}+\frac{1}{3}v\mathbf{\hat{j}}\]
D) \[\frac{3}{2}v\mathbf{\hat{i}}+\frac{1}{4}v\mathbf{\hat{j}}\]
Correct Answer: A
Solution :
From the -law of conservation of linear momentum \[mv+(3m)(2v)=(4m)v'\] \[mv\ \mathbf{i}+6\,mv\,\mathbf{j}=4\,mv'\] \[v'=\frac{1}{4}v\,\mathbf{i}+\frac{6}{4}v\,\mathbf{j}\] \[v'=\frac{1}{4}v\,\mathbf{i}+\frac{3}{2}v\,\mathbf{j}\]You need to login to perform this action.
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