A) 30 days
B) 50 days
C) 60 days
D) 15 days
Correct Answer: B
Solution :
Active fraction at instant \[{{t}_{2}},\] \[\frac{1}{{{2}^{{{t}_{2}}/{{T}_{1/2}}}}}=\frac{1}{3}\] Active fraction at instant \[{{t}_{1}},\] \[\frac{1}{{{2}^{{{t}_{1}}/{{T}_{1/2}}}}}=\frac{2}{3}\] \[\frac{{{2}^{{{t}_{2}}/{{T}_{1/2}}}}}{{{2}^{{{t}_{1}}/{{T}_{1/2}}}}}=2\] \[{{\frac{^{{{t}_{2}}-{{t}_{1}}}}{{{_{2}}^{{{T}_{1/2}}}}}}_{=2}}\] \[{{t}_{2}}-{{t}_{1}}={{T}_{1/2}}=50\,days\]You need to login to perform this action.
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