A) 2.0
B) 1.9
C) 0.62
D) 4.5
Correct Answer: C
Solution :
\[{{A}_{2}}(g)+{{B}_{2}}2AB(g)\]The equilibrium constant is given by \[{{K}_{c}}=\frac{{{[AB]}^{2}}}{[{{A}_{2}}][{{B}_{2}}]}=\frac{{{(2.8\times {{10}^{-3}})}^{2}}}{(3.0\times {{10}^{-3}})(4.2\times {{10}^{-3}})}\] \[=\frac{7.84}{12.6}\] \[=0.62\]You need to login to perform this action.
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