A) Acetophenone
B) Methyl acetate
C) Acetamide
D) 2-hydroxypropane
Correct Answer: D
Solution :
Out of the given compounds, only\[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\](2-hydroxyprepane)gives yellow precipitate with iodine and alkali (iodoform test).But \[C{{H}_{3}}-COO-C{{H}_{3}}\](methyl acetate), \[C{{H}_{3}}-CO-N{{H}_{2}}\](accetamide), do not perform this test because \[\alpha -H\]is not active due to +M effect of nearby group. \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}+4{{I}_{2}}+6NaOH\] \[\xrightarrow{{}}\underset{\begin{smallmatrix} Iodoform \\ (yellow\,ppt) \end{smallmatrix}}{\mathop{CH{{I}_{3}}}}\,\downarrow +C{{H}_{3}}COONa+5NaI+5{{H}_{2}}O\]You need to login to perform this action.
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